Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
3. | 2406 | 139 | 2 | 69.5000 |
Su | 1831 | 152 | 3 | 50.6667 |
Esta | 2005 | 140 | 3 | 46.6667 |
También | 2452 | 88 | 2 | 44.0000 |
Los | 10674 | 708 | 17 | 41.6471 |
Las | 5199 | 368 | 9 | 40.8889 |
El | 36505 | 1747 | 46 | 37.9783 |
La | 26397 | 1495 | 42 | 35.5952 |
P. | 420 | 35 | 1 | 35.0000 |
En | 19240 | 332 | 10 | 33.2000 |
Entre | 1194 | 33 | 1 | 33.0000 |
Sus | 473 | 33 | 1 | 33.0000 |
Se | 3805 | 188 | 6 | 31.3333 |
Para | 3139 | 123 | 4 | 30.7500 |
ciento | 3910 | 29 | 1 | 29.0000 |
Y | 6170 | 151 | 6 | 25.1667 |
Como | 1567 | 72 | 3 | 24.0000 |
La primera | 305 | 20 | 1 | 20.0000 |
Un | 3460 | 239 | 12 | 19.9167 |
Una | 2861 | 179 | 9 | 19.8889 |
Word | Frequency | Number of right neighbors | Number of left neighbors | Ratio |
---|---|---|---|---|
millones | 7457 | 17 | 400 | 0.0425 |
alrededor | 864 | 2 | 34 | 0.0588 |
miles | 746 | 1 | 17 | 0.0588 |
capaz | 453 | 1 | 17 | 0.0588 |
relacionados | 210 | 1 | 15 | 0.0667 |
capaces | 260 | 1 | 13 | 0.0769 |
Responses | 78 | 1 | 13 | 0.0769 |
dentro | 1580 | 4 | 50 | 0.0800 |
cientos | 347 | 1 | 11 | 0.0909 |
decenas | 329 | 1 | 11 | 0.0909 |
consiste | 231 | 1 | 11 | 0.0909 |
constancia | 81 | 1 | 11 | 0.0909 |
cerca | 1586 | 4 | 42 | 0.0952 |
Peña | 488 | 1 | 10 | 0.1000 |
tratando | 175 | 1 | 10 | 0.1000 |
finales | 763 | 2 | 19 | 0.1053 |
junto | 1766 | 3 | 27 | 0.1111 |
volver | 756 | 4 | 36 | 0.1111 |
entrar | 635 | 4 | 36 | 0.1111 |
Benedicto | 244 | 1 | 9 | 0.1111 |
In this subsection, we compute the ratio of the number of right neighbors and the number of left neighbors. Again, we look for words with extreme ratios:
Data for first table:
select word,w.freq,aa.cnt, bb.cnt,aa.cnt/bb.cnt as r from words w, (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where w_id=aa.w1_id and aa.w1_id=bb.w2_id order by r desc limit 20;
Diagram data:
select aa.cnt, bb.cnt from (select w1_id,count(c.w2_id) as cnt from co_n c where w1_id>100 group by w1_id) aa, (select w2_id,count(c.w1_id) as cnt from co_n c where w2_id>100 group by w2_id) bb where aa.w1_id=bb.w2_id;
5.1.7.1 Number of NN co-occurrences vs. Frequency I
5.1.7.2 Number of NN co-occurrences vs. Frequency II